In Wilkinson's catalyst,the hybridization of the central metal ion and its shape are respectively:
- A$sp^3d,$ trigonal bipyramidal
- B$d^2sp^3,$ octahedral
- C$dsp^2,$ square planar
- D$sp^3,$ tetrahedral
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Similar Questions
How many unpaired electrons are present in the cobalt ion in the $+3$ oxidation state prior to hybridization in the $[CoF_6]^{3-}$ complex ion?
The structure of $K[PtCl_3(C_2H_4)]$ and hybridization of $Pt$ respectively are:
Difficult
View SolutionMatch each set of hybrid orbitals from $LIST-I$ with complex(es) given in $LIST-II$. The correct option is
$LIST-I$ $LIST-II$ $P. dsp^2$ $1. [FeF_6]^{4-}$ $Q. sp^3$ $2. [Ti(H_2O)_3Cl_3]$ $R. sp^3d^2$ $3. [Cr(NH_3)_6]^{3+}$ $S. d^2sp^3$ $4. [FeCl_4]^{2-}$ $5. Ni(CO)_4$ $6. [Ni(CN)_4]^{2-}$
| $LIST-I$ | $LIST-II$ |
| $P. dsp^2$ | $1. [FeF_6]^{4-}$ |
| $Q. sp^3$ | $2. [Ti(H_2O)_3Cl_3]$ |
| $R. sp^3d^2$ | $3. [Cr(NH_3)_6]^{3+}$ |
| $S. d^2sp^3$ | $4. [FeCl_4]^{2-}$ |
| $5. Ni(CO)_4$ | |
| $6. [Ni(CN)_4]^{2-}$ |
MediumIIT 2018
View Solution$Ni(CO)_4$ is
MediumKVPY 2014
View SolutionThe correct order of hybridization of the central atom in the following species $NH_3$,$[PtCl_4]^{2-}$,$PCl_5$,and $BCl_3$ is
DifficultIIT 2001
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