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(B) The formula for the position of the $n^{th}$ bright fringe (maxima) in Young's double slit experiment is given by $x_n = \frac{n \lambda D}{d}$.Gi

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$1.5$

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(B) The formula for the position of the $n^{th}$ bright fringe (maxima) in Young's double slit experiment is given by $x_n = \frac{n \lambda D}{d}$.Given values are:$\lambda = 5000\;\mathring{A} = 5000 	imes 10^{-10}\;m = 5 	imes 10^{-7}\;m$$d = 0.2\;mm = 0.2 	imes 10^{-3}\;m = 2 	imes 10^{-4}\;m$$D = 200\;cm = 2\;m$For the third maximum, $n = 3$.Substituting these values into the formula:$x_3 = \frac{3 	imes (5 	imes 10^{-7}\;m) 	imes (2\;m)}{2 	imes 10^{-4}\;m}$$x_3 = \frac{30 	imes 10^{-7}}{2 	imes 10^{-4}}\;m = 15 	imes 10^{-3}\;m = 1.5 	imes 10^{-2}\;m = 1.5\;cm$.Therefore, the third maximum is at $x = 1.5\;cm$.

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