In Young’s double slit experiment,a minimum is obtained when the phase difference of superimposing waves is:

In a Young's experiment,when $n$ coherent sources of equal intensity $I_0$ are used,the resultant intensity is $I_1$. When $n$ incoherent sources of equal intensity $I_0$ are used,the resultant intensity is $I_2$. What are the values of $I_1$ and $I_2$?

In a Young's double-slit experiment, the distance between two coherent sources is $0.90 \, mm$ and the distance from the sources to the screen is $1 \, m$. If the distance of the second bright fringe from the center of the central bright fringe is $1 \, mm$, find the wavelength of the light used.

In a Young's double slit experiment,the distance between the two identical slits is $6.1$ times larger than the slit width. Then the number of intensity maxima observed within the central maximum of the single slit diffraction pattern is

In Young's double slit experiment, the width of the second slit is double the width of the first slit. Consequently, the amplitude of the light from the two slits is different. If $I_m$ is the maximum intensity, the resultant intensity $I$ when they interfere with a phase difference of $\phi$ is given by:

In Young's double slit experiment,if one of the slits is closed fully,then in the interference pattern: