Increasing order of boiling points in the fol | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The boiling point of a compound depends on intermolecular forces such as dipole-dipole interactions and hydrogen bonding. $1$. $CH_3COOH$ (acetic

Vedclass · Accepted Answer

$II < IV < III < I$

Vedclass · Answer

(A) The boiling point of a compound depends on intermolecular forces such as dipole-dipole interactions and hydrogen bonding. $1$. $CH_3COOH$ (acetic acid) exhibits strong intermolecular hydrogen bonding and exists as a dimer,resulting in the highest boiling point. $2$. $CH_3CH_2CH_2OH$ (propan$-1-$ol) also exhibits hydrogen bonding,but it is weaker than that in carboxylic acids,so it has a lower boiling point than $CH_3COOH$. $3$. $CH_3COCH_3$ (acetone) and $CH_3CH_2CHO$ (propanal) are polar molecules exhibiting dipole-dipole interactions. Acetone $(CH_3COCH_3)$ has a higher boiling point than propanal $(CH_3CH_2CHO)$ due to higher molecular polarity and stronger dipole-dipole interactions. $4$. Comparing all,the order is: $CH_3CH_2CHO < CH_3COCH_3 < CH_3CH_2CH_2OH < CH_3COOH$,which corresponds to $II < IV < III < I$.

Increasing order of boiling points in the following compounds is:
$I$. $CH_3COOH$
$II$. $CH_3CH_2CHO$
$III$. $CH_3CH_2CH_2OH$
$IV$. $CH_3COCH_3$

Similar Questions

The product $(A)$ obtained is:

The acidity of compounds $I-IV$ in water follows the order:
$I.$ ethanol
$II.$ acetic acid
$III.$ phenol
$IV.$ acetonitrile

Which of the following carboxylic acids could be resolved by reaction with an enantiomerically pure chiral amine?

Which of the following tetracarboxylic acids forms a di-anhydride upon heating?

Saponification (basic hydrolysis) of $C_6H_5-CO-^{18}OCH_3$ will yield. [$^{18}O$ = mass $-18$ isotope of oxygen]

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Increasing order of boiling points in the following compounds is:$I$. $CH_3COOH$$II$. $CH_3CH_2CHO$$III$. $CH_3CH_2CH_2OH$$IV$. $CH_3COCH_3$