Initially $n$ identical capacitors are joined in parallel and are charged to potential $V$. Now they are separated and joined in series. Then

  • A
    Potential difference becomes $n V$ and energy remains the same.
  • B
    Potential difference is $n V$ and energy increases $n$ times.
  • C
    Potential difference is $V$ and total energy of combination remains same.
  • D
    Potential difference remains the same and the energy increases $n$ times.

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Similar Questions

Four identical thin, square metal sheets, $S_1, S_2, S_3$, and $S_4$, each of side $a$ are kept parallel to each other with equal distance $d( < < a)$ between them, as shown in the figure. Let $C_0 = \varepsilon_0 a^2 / d$, where $\varepsilon_0$ is the permittivity of free space.
Match the quantities mentioned in $List-I$ with their values in $List-II$ and choose the correct option.
$List-I$$List-II$
$(P)$ The capacitance between $S_1$ and $S_4$, with $S_2$ and $S_3$ not connected, is$(1)$ $3 C_0$
$(Q)$ The capacitance between $S_1$ and $S_4$, with $S_2$ shorted to $S_3$, is$(2)$ $C_0 / 2$
$(R)$ The capacitance between $S_1$ and $S_3$, with $S_2$ shorted to $S_4$, is$(3)$ $C_0 / 3$
$(S)$ The capacitance between $S_1$ and $S_2$, with $S_3$ shorted to $S_1$, and $S_2$ shorted to $S_4$, is$(4)$ $2 C_0 / 3$
$(5)$ $2 C_0$

In the circuit shown,$q_2$ and $q_3$ are respectively (Initially all capacitors are uncharged).

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Five capacitors of capacitances $C_1 = C_2 = C_3 = C_4 = 10 \mu F$ and $C_5 = 2.5 \mu F$ are connected as shown, along with a battery of $50 \ V$. Find the equivalent capacitance and the charge on the capacitors.

Twenty-seven drops of the same size are charged at $220 \, V$ each. They combine to form a bigger drop. Calculate the potential of the bigger drop (in $V$).

For the given circuit,find the potential at point $a$. (in $V$)

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