Input waveforms A and B as shown in Fig-I are | vedclass

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(B) The circuit in Fig-$II$ consists of two $NOT$ gates followed by an $OR$ gate. Let the inputs be $A$ and $B$. The outputs of the $NOT$ gates are $\

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Fig-$(ii)$

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(B) The circuit in Fig-$II$ consists of two $NOT$ gates followed by an $OR$ gate. Let the inputs be $A$ and $B$. The outputs of the $NOT$ gates are $\bar{A}$ and $\bar{B}$ respectively. The final output $Y$ of the $OR$ gate is $Y = \bar{A} + \bar{B}$. According to De Morgan's theorem,$\bar{A} + \bar{B} = \overline{A \cdot B}$. This means the combination of gates acts as a $NAND$ gate. $A$ $NAND$ gate gives a low output $(0)$ only when both inputs are high $(1)$,and a high output $(1)$ otherwise. By observing the waveforms in Fig-$I$: - When both $A$ and $B$ are high,$Y$ is low. - In all other cases,$Y$ is high. Comparing this logic with the given options,Fig-$(ii)$ correctly represents the output waveform $Y$.

Input $A$	Input $B$	Output $Y$
$0$	$0$	$1$
$0$	$1$	$1$
$1$	$0$	$1$
$1$	$1$	$0$

Input waveforms $A$ and $B$ as shown in Fig-$I$ are applied to the combination of gates as shown in Fig-$II$. Which of the waveforms shown in Fig-$(i)$ to Fig-$(iv)$ correctly represents the output waveform $Y$?

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