The output Y of the following circuit for giv | vedclass

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(C) Let the inputs be $A$ and $B$. The circuit consists of an $OR$ gate,an $AND$ gate,and two $NOT$ gates.$1$. The upper part has an $OR$ gate with in

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$0$

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(C) Let the inputs be $A$ and $B$. The circuit consists of an $OR$ gate,an $AND$ gate,and two $NOT$ gates.$1$. The upper part has an $OR$ gate with inputs $A$ and $\bar{B}$. Its output is $(A + \bar{B})$.$2$. The lower part has an $AND$ gate with inputs $B$ and $\bar{A}$. Its output is $(B \cdot \bar{A})$.$3$. The final output $Y$ is the $AND$ operation of these two outputs: $Y = (A + \bar{B}) \cdot (B \cdot \bar{A})$.$4$. Expanding this expression: $Y = (A \cdot B \cdot \bar{A}) + (\bar{B} \cdot B \cdot \bar{A})$.$5$. Since $A \cdot \bar{A} = 0$ and $B \cdot \bar{B} = 0$,we get $Y = 0 + 0 = 0$.Thus,the output $Y$ is always $0$.

The output $Y$ of the following circuit for given inputs $A$ and $B$ is:

Similar Questions

Which of the following relations are correct according to Boolean algebra?

The truth table given below is for which gate?
$A: 0, 0, 1, 1$
$B: 0, 1, 0, 1$
$C: 1, 1, 1, 0$

Which logic gate with inputs $A$ and $B$ performs the same operation as that performed by the following circuit?

The combination of gates shown below yields:

The Boolean equation for the circuit given in the figure is

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