Isomers of hexane,based on their branching,ca | vedclass

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(B) The boiling point of alkanes depends on the surface area of the molecule. As the extent of branching increases,the surface area of the molecule de

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$III > II > I$

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(B) The boiling point of alkanes depends on the surface area of the molecule. As the extent of branching increases,the surface area of the molecule decreases,which leads to weaker van der Waals forces of attraction between the molecules. Consequently,the boiling point decreases as branching increases. In the given structures: $III$ is $n$-hexane (straight chain,no branching). $II$ represents isomers with one branch (e.g.,$2$-methylpentane or $3$-methylpentane). $I$ represents isomers with two branches (e.g.,$2,3$-dimethylbutane or $2,2$-dimethylbutane). Therefore,the order of boiling point is $III > II > I$.

Isomers of hexane,based on their branching,can be divided into three distinct classes as shown in the figure. The correct order of their boiling point is

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