Isopropyl methyl ether when treated with cold | vedclass

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Question

(B) The reaction of an unsymmetrical ether with cold $HI$ follows an $S_N2$ mechanism. In the case of isopropyl methyl ether,the nucleophile $(I^-)$ a

Vedclass · Accepted Answer

Isopropyl alcohol and methyl iodide

Vedclass · Answer

(B) The reaction of an unsymmetrical ether with cold $HI$ follows an $S_N2$ mechanism. In the case of isopropyl methyl ether,the nucleophile $(I^-)$ attacks the less sterically hindered alkyl group,which is the methyl group. Therefore,the reaction is: $(CH_3)_2CH-O-CH_3   HI 	ext{ (cold)} ightarrow (CH_3)_2CHOH   CH_3I$ Thus,the products formed are isopropyl alcohol and methyl iodide.

Isopropyl methyl ether when treated with cold hydrogen iodide $(HI)$ gives -

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