It costs Rs. 2200 to paint the inner curved s | vedclass

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(B) Given: Depth of the cylindrical vessel $(h) = 10\, m$. Total cost of painting = $Rs. 2200$. Rate of painting = $Rs. 20/m^2$.First,find the inner c

Vedclass · Accepted Answer

$96.25$

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(B) Given: Depth of the cylindrical vessel $(h) = 10\, m$. Total cost of painting = $Rs. 2200$. Rate of painting = $Rs. 20/m^2$.First,find the inner curved surface area $(CSA)$ of the vessel:$CSA = \frac{	ext{Total cost}}{	ext{Rate}} = \frac{2200}{20} = 110\, m^2$.Formula for $CSA$ of a cylinder is $2\pi rh = 110$.$2 	imes \frac{22}{7} 	imes r 	imes 10 = 110$.$r = \frac{110 	imes 7}{2 	imes 22 	imes 10} = \frac{770}{440} = 1.75\, m$ or $\frac{7}{4}\, m$.Now,find the capacity (volume) of the vessel:$V = \pi r^2 h = \frac{22}{7} 	imes (\frac{7}{4})^2 	imes 10$.$V = \frac{22}{7} 	imes \frac{49}{16} 	imes 10 = \frac{22 	imes 7 	imes 10}{16} = \frac{1540}{16} = 96.25\, m^3$.Since $1\, m^3 = 1\, kl$,the capacity is $96.25\, kl$.

It costs $Rs. 2200$ to paint the inner curved surface of a cylindrical vessel $10\, m$ deep. If the cost of painting is at the rate of $Rs. 20$ per $m^2$,find the capacity of the vessel. (in $, kl$)

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