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(B) The volume of water required to fill the tank is $440 \ m^3$ in $10 \ min$.Therefore,the volume of water flowing through the pipe per minute is $\

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$\sqrt{2}$

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(B) The volume of water required to fill the tank is $440 \ m^3$ in $10 \ min$.Therefore,the volume of water flowing through the pipe per minute is $\frac{440}{10} = 44 \ m^3/min$.The volume of water flowing through a circular pipe per minute is given by the formula $V = \pi r^2 h$,where $h$ is the speed of water per minute and $r$ is the inner radius.Given $h = 7 \ m/min$ and $V = 44 \ m^3/min$,we have:$44 = \frac{22}{7} 	imes r^2 	imes 7$Simplifying the equation:$44 = 22 	imes r^2$$r^2 = \frac{44}{22} = 2$$r = \sqrt{2} \ m$.

It is required to design a circular pipe such that water flowing through it at a speed of $7 \ m/min$ fills a tank of capacity $440 \ m^3$ in $10 \ min$. The inner radius of the pipe should be (in $m$):

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