Let A and B be two sets,then (A cup B)' cup ( | vedclass

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(A) Using De Morgan's Law,$(A \cup B)' = A' \cap B'$.So,the expression becomes $(A' \cap B') \cup (A' \cap B)$.By the distributive law,we can factor o

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$A'$

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(A) Using De Morgan's Law,$(A \cup B)' = A' \cap B'$.So,the expression becomes $(A' \cap B') \cup (A' \cap B)$.By the distributive law,we can factor out $A'$:$(A' \cap B') \cup (A' \cap B) = A' \cap (B' \cup B)$.Since $B' \cup B = U$ (the universal set),the expression simplifies to:$A' \cap U = A'$.Thus,$(A \cup B)' \cup (A' \cap B) = A'$.

Let $A$ and $B$ be two sets,then $(A \cup B)' \cup (A' \cap B)$ is equal to

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