Let Delta ABC sim Delta DEF and their areas b | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) It is given that $\Delta ABC \sim \Delta DEF$.According to the theorem of areas of similar triangles,the ratio of the areas of two similar triangl

Vedclass · Accepted Answer

$11.2$

Vedclass · Answer

(B) It is given that $\Delta ABC \sim \Delta DEF$.According to the theorem of areas of similar triangles,the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.$	herefore \frac{	ext{ar}(\Delta ABC)}{	ext{ar}(\Delta DEF)} = \left(\frac{BC}{EF}ight)^2$Given that $	ext{ar}(\Delta ABC) = 64 	ext{ cm}^2$,$	ext{ar}(\Delta DEF) = 121 	ext{ cm}^2$,and $EF = 15.4 	ext{ cm}$.$\frac{64}{121} = \left(\frac{BC}{15.4}ight)^2$Taking the square root on both sides:$\sqrt{\frac{64}{121}} = \frac{BC}{15.4}$$\frac{8}{11} = \frac{BC}{15.4}$$BC = \frac{8 	imes 15.4}{11}$$BC = 8 	imes 1.4 = 11.2 	ext{ cm}$.

Let $\Delta ABC \sim \Delta DEF$ and their areas be,respectively,$64 \text{ cm}^2$ and $121 \text{ cm}^2$. If $EF = 15.4 \text{ cm}$,find $BC$ (in $\text{cm}$).

Similar Questions

$E$ and $F$ are points on the sides $PQ$ and $PR$ respectively of a $\Delta PQR$. For the given case,state whether $EF || QR$:
$PE = 4 \, cm, QE = 4.5 \, cm, PF = 8 \, cm$ and $RF = 9 \, cm$.

Using Theorem $6.1,$ prove that a line drawn through the mid-point of one side of a triangle parallel to another side bisects the third side.

$ABC$ is an isosceles triangle right-angled at $C$. Prove that $AB^{2} = 2AC^{2}$.

$A$ ladder $10\, m$ long reaches a window $8\, m$ above the ground. Find the distance of the foot of the ladder from the base of the wall. (in $, m$)

In an equilateral triangle $ABC$,$D$ is a point on side $BC$ such that $BD = \frac{1}{3} BC$. Prove that $9 AD^{2} = 7 AB^{2}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module