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(A) Given the inequalities:$a + b < c + d \quad (i)$$b + c < d + e \quad (ii)$$c + d < e + a \quad (iii)$$d + e < a + b \quad (iv)$Adding $(i)$ and $(

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the largest is $a$ and the smallest is $b$.

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(A) Given the inequalities:$a + b $b + c $c + d $d + e Adding $(i)$ and $(iii)$:$(a + b) + (c + d) $a + b + c + d $b Adding $(ii)$ and $(iv)$:$(b + c) + (d + e) $b + c + d + e $c Adding $(i)$ and $(iv)$:$(a + b) + (d + e) $a + b + d + e $e Combining $(v), (vi), (vii)$:$b Thus,the largest value is $a$ and the smallest value is $b$.

Let $a, b, c, d, e$ be real numbers such that $a + b < c + d$,$b + c < d + e$,$c + d < e + a$,and $d + e < a + b$. Then,

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