Solve the given inequality for real x: frac{x | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given inequality: $\frac{x}{3} > \frac{x}{2} + 1$Subtract $\frac{x}{2}$ from both sides:$\frac{x}{3} - \frac{x}{2} > 1$Find a common denominator $

Vedclass · Accepted Answer

$(-\infty, -6)$

Vedclass · Answer

(A) Given inequality: $\frac{x}{3} > \frac{x}{2} + 1$Subtract $\frac{x}{2}$ from both sides:$\frac{x}{3} - \frac{x}{2} > 1$Find a common denominator $(6)$:$\frac{2x - 3x}{6} > 1$Simplify the numerator:$-\frac{x}{6} > 1$Multiply both sides by $6$:$-x > 6$Multiply by $-1$ and reverse the inequality sign:$x Thus,the solution set is $(-\infty, -6)$.

Solve the given inequality for real $x$: $\frac{x}{3} > \frac{x}{2} + 1$

Similar Questions

Solve $-5 \leq \frac{5-3x}{2} \leq 8$.

Solve the following system of linear inequalities and represent the solution graphically on a number line:
$3x - 7 > 2(x - 6), 6 - x > 11 - 2x$

Let $a, b, c, d, e$ be real numbers such that $a + b < c + d$,$b + c < d + e$,$c + d < e + a$,and $d + e < a + b$. Then,

If $|x+2| \leq 8$ then $x \in$

Solve the following inequality and represent it on a number line: $\frac{x-1}{2}+5 \geq \frac{2x-1}{3}+15$

Vedclass Test Series

Exam Paper Generator

Online Exam Module