Let $f(x) = \frac{\sin(x-a) + \sin(x+a)}{\cos(x-a) - \cos(x+a)}$,then
- A$f(x+2\pi) = f(x)$ but $f(x+\alpha) \neq f(x)$ for any $0 < \alpha < 2\pi$
- B$f$ is a strictly increasing function
- C$f$ is a strictly decreasing function
- D$f$ is a constant function
Explore More
Similar Questions
If $\sum_{r=1}^{50} \tan ^{-1} \frac{1}{2 r^{2}}=p$,then the value of $\tan p$ is :
DifficultJEE MAIN 2021
View SolutionIf $\tan A$ and $\tan B$ are the roots of the quadratic equation $x^2-px+q=0$,then $\sin^2(A+B)$ is equal to
DifficultAP EAMCET 2011
View SolutionIf $\cos x = \tan y$,$\cot y = \tan z$ and $\cot z = \tan x$,then $\sin x$ equals to
DifficultAP EAMCET 2014
View Solution$\tan 81^{\circ}-\tan 63^{\circ}-\tan 27^{\circ}+\tan 9^{\circ}$ equals to
DifficultTS EAMCET 2014
View SolutionIf $\operatorname{cosec} \theta = \frac{p+q}{p-q}$,then $\cot \left(\frac{\pi}{4} + \frac{\theta}{2}\right)$ is equal to
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo