Let $ABC$ be a triangle and $P$ be a point inside $ABC$ such that $\overrightarrow{PA} + 2\overrightarrow{PB} + 3\overrightarrow{PC} = \vec{0}$. The ratio of the area of $\triangle ABC$ to that of $\triangle APC$ is

  • A
    $2$
  • B
    $\frac{3}{2}$
  • C
    $\frac{5}{3}$
  • D
    $3$

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