Let $\overrightarrow{a}=2 \hat{i}+\hat{j}-\hat{k}$ and $\overrightarrow{b}=((\overrightarrow{a} \times(\hat{i}+\hat{j})) \times \hat{i}) \times \hat{i}$. Then the square of the projection of $\vec{a}$ on $\vec{b}$ is:

  • A
    $\frac{1}{5}$
  • B
    $2$
  • C
    $\frac{1}{3}$
  • D
    $\frac{2}{3}$

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