Let $X = \{(x, y) \in \mathbb{Z} \times \mathbb{Z} : \frac{x^2}{8} + \frac{y^2}{20} < 1 \text{ and } y^2 < 5x\}$. Three distinct points $P, Q,$ and $R$ are randomly chosen from $X$. Then the probability that $P, Q,$ and $R$ form a triangle whose area is a positive integer is

  • A
    $\frac{71}{220}$
  • B
    $\frac{73}{220}$
  • C
    $\frac{79}{220}$
  • D
    $\frac{83}{220}$

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