Let $O$ be the origin,the point $A$ be $z_1 = \sqrt{3} + 2\sqrt{2}i$,and the point $B(z_2)$ be such that $\sqrt{3}|z_2| = |z_1|$ and $\arg(z_2) = \arg(z_1) + \frac{\pi}{6}$. Then:

  • A
    area of triangle $ABO$ is $\frac{11}{\sqrt{3}}$
  • B
    $ABO$ is a scalene triangle
  • C
    area of triangle $ABO$ is $\frac{11}{4}$
  • D
    $ABO$ is an obtuse angled isosceles triangle

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