Let $\bar{a}$ and $\bar{b}$ be two vectors such that $|\bar{a}|=1$,$|\bar{b}|=4$,and $\bar{a} \cdot \bar{b}=2$. If $\bar{c}=(2 \bar{a} \times \bar{b})-3 \bar{b}$,then the angle between $\bar{b}$ and $\bar{c}$ is

  • A
    $\frac{\pi}{3}$
  • B
    $\frac{\pi}{6}$
  • C
    $\frac{3 \pi}{4}$
  • D
    $\frac{5 \pi}{6}$

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