Let $f(x) = x^3$ and $g(x) = 3^x$,then the quadratic equation whose roots are solutions of the equation $(f \circ g)(x) = (g \circ f)(x)$ (for $x \neq 0$) is

  • A
    $x^2 - 6x + 3 = 0$
  • B
    $x^2 - 6x + 9 = 0$
  • C
    $x^2 - x + 3 = 0$
  • D
    $x^2 - 3 = 0$

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