Let $\vec{OA} = -4\hat{i} + 3\hat{k}$ and $\vec{OB} = 14\hat{i} + 2\hat{j} - 5\hat{k}$. If $\vec{OD}$ bisects $\angle AOB$ and $|\vec{OD}| = \sqrt{6}$,then $\vec{OD} =$

  • A
    $\pm(\hat{i} + \hat{j} + 2\hat{k})$
  • B
    $\pm(\hat{i} + 2\hat{j} + \hat{k})$
  • C
    $\pm(2\hat{i} + \hat{j} + \hat{k})$
  • D
    $\pm \frac{1}{\sqrt{2}}(2\hat{i} + \hat{j} + \sqrt{7}\hat{k})$

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