Let $A(1, 1)$ be a point. $B$ is the image of $A$ with respect to the line $x + 2y + 2 = 0$. If $C$ is the foot of the perpendicular from $B$ on the line $3x + 4y - 10 = 0$,then $AC$ is equal to

  • A
    $\frac{1}{\sqrt{2}}$
  • B
    $3$
  • C
    $\sqrt{3}$
  • D
    $1$

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