Let $X = \left\{ \begin{bmatrix} a & b \\ c & d \end{bmatrix} : a, b, c, d \in \mathbb{R} \right\}$. If $f: X \rightarrow \mathbb{R}$ is defined by $f(A) = \det(A)$ for all $A \in X$, then $f$ is

  • A
    one-one but not onto
  • B
    onto but not one-one
  • C
    one-one and onto
  • D
    neither one-one nor onto

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