Let $f: X \rightarrow Y$ be a function and $A_y = f^{-1}(\{y\})$ for $y \in Y$. Then $A_i \cap A_j = \phi$ $(i \neq j)$ for all $i, j \in Y$ and $\bigcup_{y \in Y} A_y = X$, if

  • A
    $f$ is an onto function only
  • B
    $f$ is a one-one function only
  • C
    $f$ is any function
  • D
    $X$ and $Y$ are finite sets only

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