Medium
Let $f(x)=e^x$, $g(x)=\sin^{-1} x$ and $h(x)=f(g(x))$, then $\frac{h'(x)}{h(x)}$ is equal to
- A$\sin^{-1} x$
- B$\frac{1}{\sqrt{1-x^2}}$
- C$-\frac{1}{\sqrt{1-x^2}}$
- D$e^{\sin^{-1} x}$
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View Solution$\frac{d}{dx}(5^{\log x}) = \dots$
DifficultGUJCET 2025
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