Let $\lim _{t \rightarrow 0}(1+5 t)^{\frac{1}{t}}=K$ and $X$ be the random variable representing the number of successes in $100$ independent trials. If the probability of success in each trial is $0.05$, then the probability of getting at least one success is

  • A
    $\frac{1-K}{K}$
  • B
    $\frac{K-1}{K}$
  • C
    $\frac{K+1}{2K}$
  • D
    $\frac{5K+2}{7K}$

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