Let $(1+x+x^2)^9=a_0+a_1 x+a_2 x^2 +\ldots+a_{18} x^{18}$. Then

  • A
    $a_0+a_2+\ldots+a_{18}=a_1+a_3+\ldots+a_{17}$
  • B
    $a_0+a_2+\ldots+a_{18}$ is even
  • C
    $a_0+a_2+\ldots+a_{18}$ is divisible by $9$
  • D
    $a_0+a_2+\ldots+a_{18}$ is divisible by $3$ but not by $9$

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