Let $a, b, c$ be three real numbers such that $a + 2b + 4c = 0$. Then the equation $ax^2 + bx + c = 0$

  • A
    has both the roots complex
  • B
    has its roots lying within $-1 < x < 0$
  • C
    has one of roots equal to $\frac{1}{2}$
  • D
    has its roots lying within $2 < x < 6$

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