Let $A(2, 3, 0)$, $B(0, 3, 2)$ and $C(4, 0, 3)$ be the vertices of a triangle. Find the area of the triangle.

  • A
    $\frac{\sqrt{171}}{2} \text{ sq. units}$
  • B
    $\frac{\sqrt{172}}{2} \text{ sq. units}$
  • C
    $\frac{\sqrt{173}}{2} \text{ sq. units}$
  • D
    $\frac{\sqrt{174}}{2} \text{ sq. units}$

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