Let ${m_p}$ be the mass of a proton,${m_n}$ the mass of a neutron,${M_1}$ the mass of a $_{10}^{20}Ne$ nucleus,and ${M_2}$ the mass of a $_{20}^{40}Ca$ nucleus. Then:

$A$ heavy nucleus having mass number $200$ gets disintegrated into two small fragments of mass numbers $80$ and $120$. If binding energy per nucleon for the parent atom is $6.5 \text{ MeV}$ and for the daughter nuclei is $7 \text{ MeV}$ and $8 \text{ MeV}$ respectively, then the energy released in the decay will be: (in $\text{ MeV}$)

In the nuclear process $n \to p + e^- + \bar{\nu}$,if the masses of proton,neutron,and electron are $1.6725 \times 10^{-27} \ kg$,$1.6747 \times 10^{-27} \ kg$,and $9 \times 10^{-31} \ kg$ respectively,then the energy released is ...... $MeV$.

The energy equivalent of $0.5\, g$ of a substance is $........\, J$.

The energy equivalent of $1 \text{ kg}$ of matter is about

Find the energy equivalent of one atomic mass unit,first in $Joules$ and then in $MeV$. Using this,express the mass defect of $_{8}^{16} O$ in $MeV / c^{2}$.