Let $A, B, C$ be three angles such that $\sin A + \sin B + \sin C = 0$. Then,the value of $\frac{\sin A \sin B \sin C}{\sin 3A + \sin 3B + \sin 3C}$ (wherever defined) is:

  • A
    $12$
  • B
    $-12$
  • C
    $-\frac{1}{12}$
  • D
    $\frac{1}{12}$

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