Class 11MathematicsPair of straight linesBisectors of the angle between the lines, Point of intersection of the lines
MediumLet the equation of the pair of lines,$y=px$ and $y=qx$,be written as $(y-px)(y-qx)=0$. Then the equation of the pair of angle bisectors of the lines $x^{2}-4xy-5y^{2}=0$ is:
- A$x^{2}-3xy-y^{2}=0$
- B$x^{2}+3xy-y^{2}=0$
- C$x^{2}-3xy+y^{2}=0$
- D$x^{2}+4xy-y^{2}=0$
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Similar Questions
If pairs of straight lines $x^2-2 p x y-y^2=0$ and $x^2-2 q x y-y^2=0$ are such that each pair bisects the angle between the other pair,then:
Find the equation of the bisectors of the angles between the lines represented by the equation $2x^{2} - 7xy + 3y^{2} = 0$.
Difficult
View SolutionIf $\alpha$ represents the square of the distance between the origin and the point of intersection of the lines $x^2-y^2-x+3y-2=0$ and $\beta$ represents the product of the perpendicular distances from the origin to the pair of lines,then $\alpha \beta=$
If the lines represented by $x^2 - 2pxy - y^2 = 0$ are rotated about the origin by an angle $\theta$ in clockwise and counter-clockwise directions respectively,then the equation of the bisector of the angle between the lines in the new position is:
Difficult
View SolutionThe line $x - 2y = 0$ will be a bisector of the angle between the lines represented by the equation ${x^2} - 2hxy - 2{y^2} = 0$,if $h = $
Medium
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