Let N be the least six-digit number which,whe | vedclass

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(C) First,find the $LCM$ of $4, 6, 10,$ and $15$.$4 = 2^2$$6 = 2 	imes 3$$10 = 2 	imes 5$$15 = 3 	imes 5$$LCM = 2^2 	imes 3 	imes 5 = 60$.The sma

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$5$

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(C) First,find the $LCM$ of $4, 6, 10,$ and $15$.$4 = 2^2$$6 = 2 	imes 3$$10 = 2 	imes 5$$15 = 3 	imes 5$$LCM = 2^2 	imes 3 	imes 5 = 60$.The smallest six-digit number is $100000$.Divide $100000$ by $60$:$100000 = 60 	imes 1666 + 40$.To find the smallest six-digit number exactly divisible by $60$,we add $(60 - 40) = 20$ to $100000$.So,the number is $100000 + 20 = 100020$.Since the number must leave a remainder of $2$ in each case,we add $2$ to this result:$N = 100020 + 2 = 100022$.The sum of the digits of $N$ is $1 + 0 + 0 + 0 + 2 + 2 = 5$.

Let $N$ be the least six-digit number which,when divided by $4, 6, 10,$ and $15,$ leaves the same remainder of $2$ in each case. The sum of the digits in $N$ is:

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