Two pipes of length 1.5, m and 1.2, m are to | vedclass

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(C) To find the greatest length of the pipe pieces of the same size that can be cut from both pipes without any remainder,we need to calculate the Hig

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$0.3$

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(C) To find the greatest length of the pipe pieces of the same size that can be cut from both pipes without any remainder,we need to calculate the Highest Common Factor $(HCF)$ of the two lengths.Given lengths are $1.5\, m$ and $1.2\, m$.To simplify,we can express these in terms of decimeters or multiply by $10$: $15$ and $12$.The factors of $15$ are $1, 3, 5, 15$.The factors of $12$ are $1, 2, 3, 4, 6, 12$.The greatest common factor of $15$ and $12$ is $3$.Therefore,the $HCF$ of $1.5$ and $1.2$ is $0.3\, m$.

Two pipes of length $1.5\, m$ and $1.2\, m$ are to be cut into equal pieces without leaving any extra length of pipes. The greatest length of the pipe pieces of same size which can be cut from these two lengths will be (in $metre$)

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