The number of prime factors in the expression | vedclass

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(B) To find the number of prime factors,first express the base $6$ as a product of its prime factors: $6 = 2 	imes 3$.Substituting this into the expr

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$64$

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(B) To find the number of prime factors,first express the base $6$ as a product of its prime factors: $6 = 2 	imes 3$.Substituting this into the expression,we get $(2 	imes 3)^{10} 	imes (7)^{17} 	imes (11)^{27} = 2^{10} 	imes 3^{10} 	imes 7^{17} 	imes 11^{27}$.The total number of prime factors is the sum of the exponents of these prime numbers.Total number of prime factors $= 10 + 10 + 17 + 27 = 64$.

The number of prime factors in the expression $(6)^{10} \times (7)^{17} \times (11)^{27}$ is

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