Let the relation R on the set M = {1, 2, 3, d | vedclass

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(B) Given the relation $R = \{(x, y) : 4y = 5x - 3, x, y \in M\}$ where $M = \{1, 2, 3, \dots, 16\}$.We find the elements $(x, y)$ that satisfy the eq

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(B) Given the relation $R = \{(x, y) : 4y = 5x - 3, x, y \in M\}$ where $M = \{1, 2, 3, \dots, 16\}$.We find the elements $(x, y)$ that satisfy the equation $4y = 5x - 3$:If $x = 3$, $4y = 5(3) - 3 = 12 \implies y = 3$. So, $(3, 3) \in R$.If $x = 7$, $4y = 5(7) - 3 = 32 \implies y = 8$. So, $(7, 8) \in R$.If $x = 11$, $4y = 5(11) - 3 = 52 \implies y = 13$. So, $(11, 13) \in R$.If $x = 15$, $4y = 5(15) - 3 = 72 \implies y = 18$, but $18 
otin M$.Thus, $R = \{(3, 3), (7, 8), (11, 13)\}$.For $R$ to be symmetric, if $(a, b) \in R$, then $(b, a)$ must also be in $R$.Here, $(7, 8) \in R$ implies $(8, 7)$ must be in $R$, and $(11, 13) \in R$ implies $(13, 11)$ must be in $R$.$(3, 3)$ is already symmetric.Therefore, we need to add $2$ elements: $(8, 7)$ and $(13, 11)$.

Let the relation $R$ on the set $M = \{1, 2, 3, \dots, 16\}$ be given by $R = \{(x, y) : 4y = 5x - 3, x, y \in M\}$. Then the minimum number of elements required to be added in $R$, in order to make the relation symmetric, is equal to

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