Let the vectors vec{a} and vec{b} be such tha | vedclass

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(A) It is given that $|\vec{a}|=3$ and $|\vec{b}|=\frac{\sqrt{2}}{3}$.We know that the magnitude of the cross product is given by $|\vec{a} 	imes \ve

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$\frac{\pi}{4}$

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(A) It is given that $|\vec{a}|=3$ and $|\vec{b}|=\frac{\sqrt{2}}{3}$.We know that the magnitude of the cross product is given by $|\vec{a} 	imes \vec{b}| = |\vec{a}| |\vec{b}| \sin 	heta$,where $	heta$ is the angle between $\vec{a}$ and $\vec{b}$.Since $\vec{a} 	imes \vec{b}$ is a unit vector,its magnitude must be $1$,i.e.,$|\vec{a} 	imes \vec{b}| = 1$.Substituting the given values,we get:$3 	imes \frac{\sqrt{2}}{3} 	imes \sin 	heta = 1$$\sqrt{2} \sin 	heta = 1$$\sin 	heta = \frac{1}{\sqrt{2}}$Since $\sin 	heta = \frac{1}{\sqrt{2}}$,the angle $	heta = \frac{\pi}{4}$.Thus,$\vec{a} 	imes \vec{b}$ is a unit vector if the angle between $\vec{a}$ and $\vec{b}$ is $\frac{\pi}{4}$.

Let the vectors $\vec{a}$ and $\vec{b}$ be such that $|\vec{a}|=3$ and $|\vec{b}|=\frac{\sqrt{2}}{3}$. Then $\vec{a} \times \vec{b}$ is a unit vector if the angle between $\vec{a}$ and $\vec{b}$ is

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