The magnitude of the vector resulting from the addition of two vectors,$6\hat{i} + 7\hat{j}$ and $3\hat{i} + 4\hat{j}$,is:

When $n$ vectors of different magnitudes are added,we get a null vector. Then the value of $n$ cannot be

Forces $F_1$ and $F_2$ act on a point mass in two mutually perpendicular directions. The resultant force on the point mass will be

$\overrightarrow{A}$ and $\overrightarrow{B}$ are two vectors of equal magnitudes and $\theta$ is the angle between them. The angle between $\overrightarrow{A}$ or $\overrightarrow{B}$ with their resultant is

Two forces whose magnitudes are in the ratio $5:3$ are acting at a point at an angle $60^{\circ}$ simultaneously. If the resultant of the two forces is $35 \ N$,then the magnitudes of the two forces respectively are

The direction cosines of vector $(A - B)$,if $A = 2\hat{i} + 3\hat{j} + \hat{k}$ and $B = 2\hat{i} + 2\hat{j} + 3\hat{k}$,are: