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(A) The reaction involves the dehydration of an alcohol in the presence of an acid catalyst $(H^+)$ and heat $(\Delta)$.$1$. Protonation of the $-OH$

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(A) The reaction involves the dehydration of an alcohol in the presence of an acid catalyst $(H^+)$ and heat $(\Delta)$.$1$. Protonation of the $-OH$ group occurs to form a good leaving group $(-OH_2^+)$.$2$. Loss of water generates a primary carbocation at the end of the side chain.$3$. This primary carbocation undergoes a series of $1,2-H^-$ shifts to migrate the positive charge to the carbon adjacent to the tetralin ring,which is stabilized by the adjacent phenyl groups and the ring system.$4$. Finally,the elimination of a proton from the adjacent carbon leads to the formation of the most stable alkene,which is the conjugated product where the double bond is formed between the ring and the side chain,resulting in the structure shown in option $A$.

The major product $(A)$ is:

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