Mass percentage of C, H and O in a compound a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To find the molecular formula,we first determine the empirical formula:ElementPercentageAtomic MassMolesSimplest Ratio$C$$60\%$$12$$60 / 12 = 5$$5

Vedclass · Accepted Answer

$C_3H_8O$

Vedclass · Answer

(D) To find the molecular formula,we first determine the empirical formula:ElementPercentageAtomic MassMolesSimplest Ratio$C$$60\%$$12$$60 / 12 = 5$$5 / 1.667 \approx 3$$H$$13.33\%$$1$$13.33 / 1 = 13.33$$13.33 / 1.667 \approx 8$$O$$26.67\%$$16$$26.67 / 16 = 1.667$$1.667 / 1.667 = 1$Empirical formula = $C_3H_8O$Empirical formula mass = $(3 	imes 12) + (8 	imes 1) + (1 	imes 16) = 36 + 8 + 16 = 60$Given Molecular weight = $60$$n = 	ext{Molecular weight} / 	ext{Empirical formula mass} = 60 / 60 = 1$Molecular formula = $n 	imes (	ext{Empirical formula}) = 1 	imes (C_3H_8O) = C_3H_8O$.

Mass percentage of $C, H$ and $O$ in a compound are $60\%$,$13.33\%$ and $26.67\%$ respectively. The molecular weight of the compound is $60$. The molecular formula of the compound is

Similar Questions

$0.5 \ g$ of an organic compound $(X)$ with $60 \%$ carbon will produce $........ \times 10^{-1} \ g$ of $CO_2$ on complete combustion.

In an analysis,the ratio of iodine to oxygen in a certain substance is $254:80$. What will be the formula of this substance? (Atomic mass $I = 127$,$O = 16$)

An organic compound contains $C$,$H$,and $O$ in the proportion of $6 : 1 : 8$ by weight,respectively. Its vapour density is $30$. Its molecular formula will be

Analysis of an organic compound shows $C = 40\%$,$H = 13.33\%$,and $N = 46.67\%$. Its empirical formula is ....

If $1.24 \ g$ of $P$ is present in a $2.2 \ g$ sample of a compound,identify the empirical formula of the compound (Atomic mass of $P = 31 \ g/mol$,$S = 32 \ g/mol$).

Vedclass Test Series

Exam Paper Generator

Online Exam Module