Match column $-I$ and column $-II$ with the correct relation:
Column $-I$ Column $-II$
$(i).$ Prussian blue $(a).$ Presence of phosphorus
$(ii).$ Yellow precipitate $(b).$ Presence of sulphur
$(iii).$ Purple solution $(c).$ Presence of nitrogen
$(iv).$ Black precipitate $(d).$ Presence of chlorine

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(C) The correct matches are as follows:
$(i).$ Prussian blue is formed in the test for the presence of nitrogen $(Fe_4[Fe(CN)_6]_3)$.
$(ii).$ Yellow precipitate is formed in the test for the presence of phosphorus (ammonium phosphomolybdate).
$(iii).$ Purple solution is formed in the test for the presence of sulphur (sodium nitroprusside test).
$(iv).$ Black precipitate is formed in the test for the presence of sulphur (lead sulphide).
Therefore,the correct matching is $(i-c, ii-a, iii-b, iv-b)$.

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