The compound formed in the positive test for nitrogen with the Lassaigne solution of an organic compound is

Match List-$I$ with List-$II$.

List-$I$ (Functional group detection)	List-$II$ (Change observed during detection)
$A$. Unsaturation (Baeyer's test)	$I$. Red colour appears
$B$. Alcoholic group (Ceric ammonium nitrate test)	$II$. Silver mirror appears
$C$. Aldehyde group (Tollen's reagent)	$III$. Violet colour appears
$D$. Phenolic group ($FeCl_3$ test)	$IV$. Discharge of pink colour

Choose the correct answer from the options given below:

Match the List-$I$ with List-$II$:

List-$I$ (Reagent)	List-$II$ (Functional Group detected)
$A$. Sodium bicarbonate solution	$I$. Double bond/unsaturation
$B$. Neutral ferric chloride	$II$. Carboxylic acid
$C$. Ceric ammonium nitrate	$III$. Phenolic $-OH$
$D$. Alkaline $KMnO_4$	$IV$. Alcoholic $-OH$

Choose the correct answer from the options given below:

For testing halogens in an organic compound with $AgNO_{3}$ solution,sodium extract (Lassaigne's test) is acidified with dilute $HNO_{3}$. What will happen if a student acidifies the extract with dilute $H_{2}SO_{4}$ in place of dilute $HNO_{3}$?

Identify the binary mixture$(s)$ that can be separated into individual compounds by differential extraction,as shown in the given scheme.
$(A)$ $C_6H_5OH$ and $C_6H_5COOH$
$(B)$ $C_6H_5COOH$ and $C_6H_5CH_2OH$
$(C)$ $C_6H_5CH_2OH$ and $C_6H_5OH$
$(D)$ $C_6H_5CH_2OH$ and $C_6H_5CH_2COOH$

Match List-$I$ with List-$II$:

List-$I$ (Test/Reagents/Observation)	List-$II$ (Species detected)
$(a)$ Lassaigne's Test	$(i)$ Carbon
$(b)$ $Cu(II)$ oxide	$(ii)$ Sulphur
$(c)$ Silver nitrate	$(iii)$ $N, S, P,$ and halogen
$(d)$ The sodium fusion extract gives black precipitate with acetic acid and lead acetate	$(iv)$ Halogen specifically

The correct match is: