Match List-I with List-II for the following r | vedclass

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(B) The reactions of glucose provide evidence for its structure:$a$. Acetic anhydride reacts with glucose to form glucose pentaacetate,indicating the

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$a-iii, b-i, c-ii, d-iv$

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(B) The reactions of glucose provide evidence for its structure:$a$. Acetic anhydride reacts with glucose to form glucose pentaacetate,indicating the presence of $5$ hydroxyl groups $(iii)$.$b$. Bromine water is a mild oxidizing agent that oxidizes the aldehyde group of glucose to gluconic acid,indicating the presence of an aldehyde group $(i)$.$c$. Hydroiodic acid $(HI)$ reduces glucose to $n$-hexane,confirming that glucose has a straight chain of $6$ carbon atoms $(ii)$.$d$. Hydrogen cyanide $(HCN)$ reacts with the carbonyl group of glucose to form a cyanohydrin,indicating the presence of a carbonyl group $(iv)$.Therefore,the correct matching is $a-iii, b-i, c-ii, d-iv$.

List-$I$ (Reagents)	List-$II$ (Structural prediction)
$a$. Acetic anhydride	$i$. Glucose has an aldehyde group
$b$. Bromine water	$ii$. Glucose has a straight chain of six carbon atoms
$c$. Hydroiodic acid	$iii$. Glucose has five hydroxyl groups
$d$. Hydrogen cyanide	$iv$. Glucose has a carbonyl group

List-$I$	List-$II$
$(a)$. Sucrose	$(i)$. $\beta-D$-Galactose and $\beta-D$-Glucose
$(b)$. Lactose	$(ii)$. $\alpha-D$-Glucose and $\beta-D$-Fructose
$(c)$. Maltose	$(iii)$. $\alpha-D$-Glucose and $\alpha-D$-Glucose

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