Match List I with List II: (A). Inductive eff | vedclass

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(A) Step $1$: Inductive effect is the permanent displacement of $\sigma$ electrons along a carbon chain due to the difference in electronegativity of

Vedclass · Accepted Answer

$(A) - (IV), (B) - (III), (C) - (I)$

Vedclass · Answer

(A) Step $1$: Inductive effect is the permanent displacement of $\sigma$ electrons along a carbon chain due to the difference in electronegativity of atoms or groups. Thus, $(A) - (IV)$.Step $2$: Hyper-conjugation involves the delocalization of $\sigma$ electrons of a $C-H$ bond of an alkyl group directly attached to an unsaturated system. Thus, $(B) - (III)$.Step $3$: Resonance effect involves the delocalization of $\pi$ electrons or lone pair electrons in a conjugated system. Thus, $(C) - (I)$.Step $4$: Combining these, we get $(A) - (IV), (B) - (III), (C) - (I)$. Therefore, the correct option is $A$.

$(A)$. Inductive effect	$(I)$. Delocalization of $\pi$ electrons
$(B)$. Hyper-conjugation	$(II)$. Displacement of $\pi$ electrons
$(C)$. Resonance effect	$(III)$. Delocalization of $\sigma$ electrons
	$(IV)$. Displacement of $\sigma$ electrons

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