Match List-I with List-II : List-I (Spec | vedclass

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(A) To determine the number of lone pairs on the central atom $(Xe)$ in each species:$1$. $XeF_{2}$: $Xe$ has $8$ valence electrons. $2$ are used for

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$a-iv, b-ii, c-i, d-iii$

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(A) To determine the number of lone pairs on the central atom $(Xe)$ in each species:$1$. $XeF_{2}$: $Xe$ has $8$ valence electrons. $2$ are used for bonding with $F$ atoms. Remaining electrons = $8-2 = 6$,which form $3$ lone pairs. Thus,$(a) - (iv)$.$2$. $XeO_{2}F_{2}$: $Xe$ has $8$ valence electrons. $2$ are used for $F$ atoms and $4$ are used for $2$ double-bonded $O$ atoms. Remaining electrons = $8-2-4 = 2$,which form $1$ lone pair. Thus,$(b) - (ii)$.$3$. $XeO_{3}F_{2}$: $Xe$ has $8$ valence electrons. $2$ are used for $F$ atoms and $6$ are used for $3$ double-bonded $O$ atoms. Remaining electrons = $8-2-6 = 0$. Thus,$(c) - (i)$.$4$. $XeF_{4}$: $Xe$ has $8$ valence electrons. $4$ are used for bonding with $F$ atoms. Remaining electrons = $8-4 = 4$,which form $2$ lone pairs. Thus,$(d) - (iii)$.Therefore,the correct matching is $a-iv, b-ii, c-i, d-iii$.

List-$I$ (Species)	List-$II$ (Number of lone pairs of electrons on the central atom)
$(a)$ $XeF_{2}$	$(i)$ $0$
$(b)$ $XeO_{2}F_{2}$	$(ii)$ $1$
$(c)$ $XeO_{3}F_{2}$	$(iii)$ $2$
$(d)$ $XeF_{4}$	$(iv)$ $3$

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Match List-$I$ with List-$II$ : List-$I$ (Species) List-$II$ (Number of lone pairs of electrons on the central atom) $(a)$ $XeF_{2}$ $(i)$ $0$ $(b)$ $XeO_{2}F_{2}$ $(ii)$ $1$ $(c)$ $XeO_{3}F_{2}$ $(iii)$ $2$ $(d)$ $XeF_{4}$ $(iv)$ $3$ Choose the most appropriate answer from the options given below: