The correct order of H-N-H bond angles of amm | vedclass

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(B) According to $VSEPR$ theory,the bond angle depends on the number of lone pairs on the central nitrogen atom.As the number of lone pairs increases,

Vedclass · Accepted Answer

$NH_4^{+} > NH_3 > NH_2^{-}$

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(B) According to $VSEPR$ theory,the bond angle depends on the number of lone pairs on the central nitrogen atom.As the number of lone pairs increases,the repulsion between lone pair-bond pair increases,which compresses the bond angle.- $NH_4^{+}$: $0$ lone pairs,$4$ bond pairs,bond angle $\approx 109^{\circ} 28'$.- $NH_3$: $1$ lone pair,$3$ bond pairs,bond angle $\approx 107^{\circ}$.- $NH_2^{-}$: $2$ lone pairs,$2$ bond pairs,bond angle $\approx 105^{\circ}$.Therefore,the correct order of bond angles is $NH_4^{+} > NH_3 > NH_2^{-}$.

The correct order of $H-N-H$ bond angles of ammonia,ammonium ion,and amide ion is:

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