Match the following:List-IList-II(A) Delta U | vedclass

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(C) The correct match is $A-II, B-V, C-III, D-I$.Explanations:$(A) \rightarrow II$: For an adiabatic wall,$q = 0$. From the first law of thermodynamic

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$A$$B$$C$$D$$II$$V$$III$$I$

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(C) The correct match is $A-II, B-V, C-III, D-I$.Explanations:$(A) \rightarrow II$: For an adiabatic wall,$q = 0$. From the first law of thermodynamics,$\Delta U = q + W$,so $\Delta U = W_{ad}$.$(B) \rightarrow V$: For a closed system,both heat $(q)$ and work $(W)$ can be exchanged,following $\Delta U = q - W$ (where $W$ is work done by the system).$(C) \rightarrow III$: For thermally conducting walls,heat exchange occurs. The specific case $\Delta U = -q$ implies work done is zero or specific conditions are met.$(D) \rightarrow I$: In an isothermal reversible expansion,$\Delta T = 0$,therefore $\Delta U = C_V \Delta T = 0$.

List-$I$	List-$II$
$(A) \Delta U = W_{ad}$	$I.$ Isothermal reversible expansion
$(B) \Delta U = q - W$	$II.$ Wall is adiabatic
$(C) \Delta U = -q$	$III.$ Thermally conducting walls
$(D) \Delta U = 0$	$IV.$ Isolated system
	$V.$ Closed system

Match the following:
List-$I$ List-$II$
$(A) \Delta U = W_{ad}$ $I.$ Isothermal reversible expansion
$(B) \Delta U = q - W$ $II.$ Wall is adiabatic
$(C) \Delta U = -q$ $III.$ Thermally conducting walls
$(D) \Delta U = 0$ $IV.$ Isolated system
$V.$ Closed system

The correct answer is

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Match the following:List-$I$List-$II$$(A) \Delta U = W_{ad}$$I.$ Isothermal reversible expansion$(B) \Delta U = q - W$$II.$ Wall is adiabatic$(C) \Delta U = -q$$III.$ Thermally conducting walls$(D) \Delta U = 0$$IV.$ Isolated system$V.$ Closed systemThe correct answer is