Match the following:

List-$I$	List-$II$
$A$. Oxidation state of $V$ in $VOCl_2$	$I$. $0$
$B$. Number of unpaired electrons in $MnO_4^{2-}$ ion	$II$. $1$
$C$. Number of unpaired electrons in $[NiCl_4]^{2-}$ ion	$III$. $5$
$D$. This oxidation state is exhibited by all lanthanide ions	$IV$. $3$
	$V$. $4$
	$VI$. $2$

The correct answer is:

Which of the following substances are colored even in the absence of $d-d$ transitions?

Select the correct option.

Given below are two statements:
Statement $I$: The number of pairs, from the following, in which both the ions are coloured in aqueous solution is $3$: $[Sc^{3+}, Ti^{3+}], [Mn^{2+}, Cr^{2+}], [Cu^{2+}, Zn^{2+}]$ and $[Ni^{2+}, Ti^{4+}]$.
Statement $II$: $Th^{4+}$ is the strongest reducing agent among $Th^{4+}, Ce^{4+}, Gd^{3+}$ and $Eu^{2+}$.
In the light of the above statements, choose the correct answer from the options given below:

Which of the following statements are correct?
$(i)$ $V^{2+}$ liberates hydrogen from a dilute acid.
$(ii)$ The earlier members of the lanthanide series behave more like aluminium.
$(iii)$ The 'silver' $UK$ coins are made of $Cu/Ni$ alloy.
$(iv)$ The maximum oxidation state exhibited by Neptunium is $+7$.

Which of the following will give a green hydrated ion?